Investigating the concentration of the solutions inside the vacuole of a potato cell. :: essays research papers

Osmosis InvestigationWe are trying to find out what the density of the solutions is inside the vacuole of a potato cell.We will go over how the mass of the potato chips change in different saccharose solution concentrations.We will use osmosis to do this.I will be measuring and despotic many different variables, these include -The dependent Variable Weight of potato chipIndependent Variable Concentration of sucroseControl Variables consist of -1.Temperature2. locate compass of potato3.Volume of sucrose solution4.Same time for each potato chip submerged in solution5.Potato chips all(prenominal) from same potatoThe effects on the dependent variables all differ here is how the main variables in my experiment work out.Variable Effect on Dependent Variable Surface area of potato chipThe greater the surface area the more irrigate it will be able to launchSame chip from the same potatoThe genetic make-up will be the same and therefore the partly permemble membrane will be kindred Time left in the solutionThe longer spent in solution the more that is absorbedCoating on the potato chipsIf not rinsed glowering and dried after a certain period of time the chips will form a coat of sugar thus decreasing surface areaQuantitative prediction I predict that the effect of changing the sucrose concentration will be that as the concentration of the sucrose solution increases, world-class of all the mass of the chip will increase, and then the change in mass will gradually decrease until mass is lost and this mass injustice will gradually increase in amount.Because when the sucrose concentration is low, the concentration of body of water outside the cells of the potato chips will be greater than that inside, and therefore water will osmosis into the cells of the chip which will gain mass. As the concentration of sucrose increases the concentration of water outside the call will eventually become little than inside the cells of the chip and mass will be lost.Dependen tVariableInside the cells Outside the cellsDilute solution Concentrated solutionHigher water concentration Low water concentrationKey= Sucrose particle= water molecule= osmosis= partially permeable membraneIn the higher sucrose concentration solution, the net movement of water (osmosis) is to the outside of the cell, and the chip will lose mass, the cells will become plasmolysed.The chip in a low concentration of sucrose solution, is the opposite of the diagram above, in that the water osmoses into the cells of the chip, mass it gained, through osmosis of water into the plant cells, the cells will become turgid.